Bobosharif S. answered 04/23/18
Tutor
4.4
(32)
Mathematics/Statistics Tutor
log a+log b+log c =0
log(abc)=0, abc=1, 1/c=ab.
(abc)1/3≤(a+b+c)/3≤√(a2+b2+c2)/3
3≤a+b+c≤√3(a2+b2+1/(ab)2)≤3
So, a+b+c=3.
But you have to show that √3(a2+b2+1/(ab)2)≤3!