how to write a matrix A+2B=c as an equation in terms of x , where A=(2 -3

-2 5)

and B=(4 3x

0 -1)

and C= (10 -15

-2 3)

how to write a matrix A+2B=c as an equation in terms of x , where A=(2 -3

-2 5)

and B=(4 3x

0 -1)

and C= (10 -15

-2 3)

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We have:

A = [2 -3

-2 5]

2B = [8 6x

0 -2]

So A + 2B = [2+8 -3+6x

-2+0 5-2]

or

[10 -3+6x

-2 3]

To rewrite A + 2B = c

[10 (-3+6x) = [10 -15

-2 3] -2 3]

From that we see -3+6x = -15 as an equation in terms of x

So the Matrices are A+2B=C then the first number in A + the first number in B times 2 should = C.

So if you are trying to solve for x you need to note that x in in the top right section of the B matrix, so all of the numbers you are going to use will be in the top right section. that being said use the equation below.

A=-3, B=3x, C=-15. Plug in these numbers to your initial equation of A+2B=C

-3+2(3x) = -15

distribute the 2: -3 + 6x = - 15

Add 3 to both sides: 3-3+6x = -15 + 3 simplify: 6x = -12

get x by itself by dividing both sides by 6: (6x)/6 = -12/6 Simplify:

x=-2

To verify that you have the correct answer plug (-2) in for x in the equation.

-3+2( 3(-2) ) = -15

-3+2(-6) = -15

-3+(-12) = -15 or -3-12 = -15

-15 = -15 Both sides are equal when you plug in our answer for x so x=-2 is correct.

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