17.9 mL of sulfuric acid solution was required to titrate 11.12 mL of 0.109 M potassium hydroxide solution to the equivalence point. What was the molarity of

Question

the acid solution?  This is the rest of the question and please help thank you

Answer 1

H2SO4 + 2KOH ==> K2SO4 + 2H2O

Find moles of KOH used:  0.01112 L x 0.109 moles/L = moles KOH

Find moles H2SO4 neutralized:  It takes 2 moles KOH for each mole H2SO4.  Moles H2SO4 = moles KOH/2

Find molarity of H2SO4:  moles H2SO4/liters = moles H2SO4/0.0179 L = M of H2SO4