Mark M. answered 04/15/18
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Retired Math prof with teaching and tutoring experience in trig.
2cos2x + cosx - 1 = 0
(2cosx - 1)(cosx + 1) = 0
2cosx - 1 = 0 or cosx + 1 = 0
cosx = 1/2 or cosx = -1
If cosx = -1, then x = 180°
If cosx = 1/2, then x = 60° or 300°
Solutions between 0° and 360°: 60°, 180°, 300°