organic chemistry

Question

A sample of argon gas at a pressure of 0.894 atm and a temperature of 199 °C, occupies a volume of 853 mL. If the gas is heated at constant pressure until its volume is 998 mL, the temperature of the gas sample will be?

Answer 1

At constant pressure, you can use Charles' Law:

V1/T1 = V2/T2

V1 = 853 ml = 0.852 L

T1 = 199ºC + 273 = 472K

V2 =998 ml = 0.998 L

T2 = ?

0.852 L/472K = 0.998/T2

T2 = 553 K = 280ºC