J.R. S. answered 04/09/18
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As with your previous question, you use ∆T = imK to solve this problem.
∆T = change in temperature = 11ºC
i = van't Hoff factor = 3 for MgCl2
m = molality = ?
K = boiling point constant for water = 0.52ºC/m
11 = (3)(m)(0.52)
m = 7.05 moles/kg
Since the problem states that you have 555 g of water, and assuming a density of 1g/ml, that equates to 0.555 kg water.
7.05 moles/kg x 0.555 kg = 3.91 moles MgCl2
3.91 moles MgCl2 x 95.2 g/mole = 373 g MgCl2 needed