
Mark M. answered 04/04/18
Tutor
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Mathematics Teacher - NCLB Highly Qualified
0.40a0 = a0(0.5)t/2.3
0.40 = (0.5)t/2.3
ln 0.4 = (t/2.3)(ln 0.5)
-0.916 ≈ (t/2.3)(ln 0.5)
-2.107 = t ln 0.5
-2.107 = -0.693 t
3.040 ≈ t