HELP with logs

Question

log2(x+1)=3

Answer 1

Assuming log2(x+1) means log base 2 of (x+1):

 

log₂(x+1) = 3

 

2^log₂(x+1) = 2³

 

x+1 = 8

 

x = 7

Answer 2

My answer is :log2(x+1)=3 => x+1 = 2^3;

Then x=7

The reasoning is that at what power do I need to elevate 2 to obtain (x + 1) so the second equation responds to the question.