what mass in grams of mgcl2 will be produced if 3.00g of mg(oh)2 reacts

Question

help!!!!!

Answer 1

This is an incomplete question.  You state that 3.00 g of Mg(OH)2 reacts but with what?  You probably are looking at a reaction similar to Mg(OH)2 + 2HCl ==>MgCl2 + 2H2O

Moles Mg(OH)2 used = 3.00 g Mg(OH)2 x 1 mole/58.3 g = 0.0515 moles

Moles MgCl2 produced = 0.0515 moles Mg(OH)2 x 1 mole MgCl2/mole Mg(OH)2 = 0.0515 moles MgCl2

Mass MgCl2 = 0.0515 moles x 95.2 g/mole = 4.89 g