How many grams of water would boil if I added 2,552,000 J of energy to a large cauldron of 80.0 °C water?

Question

Please help with this question and how to set it up.

Answer 1

Look up the specific heat of liquid water, preferably in units of J/(g °C).

 

c = specific heat of liquid water

m = mass of the water = ?

ΔT = (100 - 80.0)°C  [You want to raise the temperature from 80°C to the boiling point of water at 100°C.]

Q = 2,552,000 J

 

Q = mcΔT ⇒

 

m = Q/(cΔT)

 

Now just plug in the numbers in appropriate units to get m in grams.  Be careful with the units.