
Andy C. answered 03/30/18
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P : sample proportion
p0 : hypothesis proportion
n : is the sample size
Then denominator D = sqrt ( p0 ( 1 - p0) / n)
The test stat is z= (p - p0)/ D
(1) n = 560 so P = 161/560 = 0.2875
D = sqrt( 0.25 * (1 - 0.25) / 560 ) = sqrt ( 0.25 * 0.75 / 560 ) = 0.0183 approximately
The test stat z = ( 0.2875 - 0.25 ) / 0.0183 = 2.049
Per the normal bell curve, reject the null hypothesis; statistical evidence suggests the population
proportion is not 0.25 ( potentially greater than)
(2) N=1427 P = 457/1427 = 0.3202
D = sqrt ( 0.3 * (1 - 0.3)/1427) = sqrt ( 0.3 * 0.7 / 1427) = 0.01213103 approximately
Test test stat is ( 0.3202 - 0.3) / 0.01213103 = 1.66515127
This is less than critical values for most confidence levels ( 95% certainty requires 1.96)
The statistical evidence supports the claim; accepts null hypothesis. Notice the sample size is
much larger than the previous