Chemistry help

Question

The exact mass of NaHCO3 that was weighed was 0.75g. The mass lost in the reaction was found to be 0.42 g. Calculate the experimental mass % CO2 in this solid.

Answer 1

What reaction did you use?  Did you react the NaHCO3 with acid/water?

NaHCO3 + H+ ==> Na+ + CO2 + H2O

0.75 g NaHCO3 x 1 mol/84 g = 0.00893 moles

moles CO2 theoretically formed = 0.00893

mass CO2 = 0.00893 moles x 44 g/mole = 0.393 g CO2 = Theoretical mass

Experimental mass = 0.42 g

0.42/0.75 (x100%) = 56%