chemistry problem

Question

What mass of natural gas (CH4) must you burn to emit 271 kJ of heat?
CH4(g)+2O2(g)→CO2(g)+2H2O(g)ΔH∘rxn=−802.3kJ

m=?

Answer 1

CH4(g)+2O2(g)→CO2(g)+2H2O(g)ΔH∘rxn=−802.3KJ

1 mole CH4/x mokes = 802.3 kJ/271 kJ

Solve for x to get your answer.