J.R. S. answered 03/14/18
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At STP you have
P1= 1 atm
V1 = 1.64 L
T1 = 273 K
At the other condition you have
P2 = 3.4 atm
V2 = ?
T2 = -78ºC + 273 = 195 K
P1V1/T1 = P2V2/T2 and solving for V2 you obtain
V2 = P1V1T2/P2T1 = (1 atm)(1.64 L)(195 K)/(3.4 atm)(273 K) = 0.345 liters