If 20.0g of N2 has is reacted with excess H2 gas, how many moles of NH3 (g) should be produced?

Question

Not sure how to do it. Ammonia gas is made by N2 + 3 H2 = 2 NH3

Answer 1

Moles N2 = 20.0g x 1 mol/28g = 0.714 moles

moles NH3 produced = 0.714 mole N2 x 2 mol NH3/1 mol N2 = 1.43 moles NH3