J.R. S. answered 02/08/18
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When given problems that present the % composition, it is easiest to just assume 100 g of material, and calculate based on that. Thus, in 100 g of the material, you have....
54g C = 54 g C x 1 mol/12 g = 4.5 moles C
8.1 g H = 8.1 g H x 1 mol/1 g = 8.1 moles H
37.9 g N = 37.9 g N x 1 mol/14 g = 2.7 moles N
Dividing by the smallest (2.7) in order to get whole numbers, we end up with ...
4.5 moles C/2.7 = 1.67 moles C
8.1 moles H/2.7 = 3 moles H
2.8 moles N/2.7 = 1 mole N
To get 1.67 to a whole number, we multiply by 3, and then multiply the others by 3 also.
C = 1.67 x 3 = 5 moles C
H = 3 x 3 = 9 moles H
N = 1 x 3 = 3 moles N
Empirical formula = C5H9N3
Formula weight of C5H9N3 = (5x12) + (9x1) + (3x14) = 60 + 9 + 42 = 111 g/mole
Since this is the same as the molar mass for the molecular formula, then this is the molecular formula, i.e. the molecular formula for histamine is C5H9N3