College Physics 1 LAB:5 Concurrent Forces

Question

A force vector has an x-component of 300. g and a y-component of -180. g.
A.) Find the magnitude of the force
B.) Find the direction of the force (in standard notation)
C.) What is the equilinbrant for the force?

Answer 1

(A)

 

F = √(F_x² + F_y²) = √[(300)² + (-180)²] g ≅ 349.9 g 

 

(B)

 

θ = arctan(F_y/F_x) = arctan(-180/300) ≅ -30.96°

 

The direction is 30.96º BELOW the x-axis.

 

(C)

 

The equilibrant is the equal and opposite force.

 

-F = (-300i + 180j) g