When 7.00 g of sulfur are combined with 7.00 g of oxygen, 14.00 g of sulfur dioxide (SO2) are formed. What mass of oxygen would be required to convert 4.00 g of

Question

What mass of oxygen would be required to convert 4.00 g of sulfur into sulfur trioxide (SO3)

Answer 1

2S + 3O₂ ==> 2SO₃

4 g S x 1 mole S/32g = 0.125 moles S

moles O2 needed = 0.125 mol S x 3 mol O2/2 mol S = 0.1875 mol O2 needed

0.1875 mol O2 x 32g/mol = 6 g O2 required