How far away are the 2 buildings if building A to the top of building B is 14.9 degrees and if building B is 1453 tall

Question

The angle of inclination from base of skyscraper A to the top of skyscraper B is 14.9 degrees. If skyscraper B is 1453 ft tall how far apart are the 2 skyscrapers? The bases are the same

Answer 1

Since you are given the angle of inclination and the height of building B, you can use the definition of the tangent function to find the distance x between buildings A and B.

 

tan(angle) = (opposite side)/(adjacent side)

 

tan(14.9°) = 1453ft./x, so x = 1453ft./tan(14.9°) ≅ 5,461ft.