Find the length of AB if a is located at (-2,0) and b is located at (5,0) 3 7 6 10

Question

Can you please check my answer? i got 7

Answer 1

A=(-2,0) and B=(5,0)

√[(-2-5)^2+(0-0)^2]

√(-7)^2

√49=7

both points are on the x-axis

-2 to 5 is 7 units (2 units to 0 and then 5 more units to 5)