
Arturo O. answered 01/12/18
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I assume the log is log10. I will use just V for Vout, since it is easier to type. Just evaluate the derivatives, using
d/dx logax = 1/[x ln(a)]
and the chain rule.
G = 20 log(10V)
(a)
dG/dV = [20/(10V ln10)] (10) = 20/(V ln10)
(b)
d2G/dV2 = (20/ln10)(-1/V2) = -(20/ln10)/V2