suppose the height and base of a triangle are twice the length of the height and base of another triangle.

Question

What is the ratio of the area of the smaller to the are of the larger triangle? Justify your answer.

 

I have this homework problem and I have tried to solve it on my own but I keep getting stuck as well as a couple of other problems that I am having trouble with. Please assist me

Answer 1

Triangle 1:  height = h, base = b

Area = (1/2)bh

 

Triangle 2:  height = 2h, base = 2b

Area = (1/2)(2b)(2h) = (1/2)4bh = 2bh

 

((1/2)bh)/(2bh) = (1/2)/2 = 1/4 

 

Ratio of the areas is 1:4

 

Understand?