What is the period of y=3cos(4x+♊️/2)+5

Question

What is the period of y=3cos(4x+♊️/2)+5

Answer 1

The general form is:

 

y = a·cos(b(x+c)) + d

 

where

• a = 3 = amplitude
• b = 4 = 2pi/period
• c = horizontal of phase shift
• d = 5 = vertical shift

 

The period can be found from the relation b = 2pi/period.  In your case b=4.  Solve for the period.