Find the value of each of the following

Question

solve 

 

8^2x+1=16^2x-3

 

 

find the value of Of each of the following, giving your answer an integer

 

Log₆2-Log₆12

 

 

Answer 1

8^2x+1 = 16^2x-3

 

(2³)^2x+1 = (2⁴)^2x-3

 

2^6x+3 = 2^8x-12

 

6x+3 = 8x-12

 

2x = 15

 

  x = 7.5

 

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log₆2 - log₆(12) = log₆(2/12)

 

                        = log₆(1/6) = log₆(6^-1) = -1