
Andy C. answered 12/31/17
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The compounding interest formula with annual contributions is:
P(1 + r)^Y + c[ ((1 + r)^Y - 1) / r ]
Where P is the starting principal amount which in this problem is 4500,
r is 8.1% = 0.081
Y is the number of years which is 22
and C is the annual contributions which is the same as P= 4500
4500(1.081)^22 + 4500[ ((1.081)^22-1)/0.081]
4500(5.548368111) + 4500[(5.548368111-1)/0.081]
4500((5.548368111) + 4500(68.498372)
24967.6565 +308242.674
333210.33
Part B is simply the compound interest formula, as annual contributions stop.
333210.33 (1.081)^20 = 1582091.19