
Arturo O. answered 12/11/17
Tutor
5.0
(66)
Experienced Physics Teacher for Physics Tutoring
If the normal force is not zero, then equilibrium of forces in the horizontal direction gives
Fcosθ = N
N = normal force, which points horizontally
Equilibrium of forces in vertical direction gives
Fsinθ + μN = mg
(a)
The applied force is maximum when N = 0 ⇒
Fmaxsinθ = mg
Fmax = mg/sinθ = (1.5)(9.8)/sin60° newtons ≅ 16.97 newtons
(b)
The applied force is minimum when N ≠ 0.
N = Fcosθ
Fsinθ + μ(Fcosθ) = mg
Fmin = mg/(sinθ + μcosθ) = (1.5)(9.8)/(sin60° + 0.65cos60°) newtons ≅ 12.34 newtons

Arturo O.
I this particular problem, the force of friction points vertically up because it helps keep the body from sliding down. The downward weight of the body is canceled by the upward pull of the applied force and the upward force of friction. If the applied force force is used to pull the body up, then friction opposes the applied in force. But in this problem, friction is opposing gravity to maintain equilibrium of forces in the vertical direction.
Report
12/31/17
Gnarls B.
12/31/17