
Arturo O. answered 12/09/17
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(a)
T = 5°C
x = 500 mm of Hg
h(x) = (30T + 8000)log(760/x) =[30(5) + 8000] log(760/500) m ≅ 1482 m
(b)
h = 8900 m
T = 0°C
8900 = [30(0) + 8000)]log(760/x)
8900 = 8000 log(760/x)
1.1125 = log(760/x)
101.1125 = 760/x
x = 760/101.1125 ≅ 58.7 mm of Hg
Zaya T.
1.1125 = log(760/x)?
12/09/17