J.R. S. answered 12/02/17
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Ok. But the 250 is NOT the extinction coefficient. I found it to be 2.3x105 M-1cm-1 which makes more sense. So here is the approach.
A = ecl
0.324 = 2.3x105 x c x 1
c = 0.324/2.3x105
c = 1.41x10-6 M = 1.41x10-6 moles/liter
1.41x10-6 moles/liter x 30,000 g/mole = 4.23x10-2 g/liter = 42.3 mg/liter
This is the concentration in the 2 ml filtrate that was diluted 10x
Concentration of phycocyanin in the original filtrate = 10 x 42.3 ml/liter = 423 mg/liter
Since you had 50 ml (0.05 liters) and not 1 liter, then you had 423 mg/liter x 0.05 liter = 21.15 mg in the 50 ml
This was taken out of 100 ml so in the 100 ml you had 2 x 21.15 mg = 42.3 mg of phycocyanin.
This was equivalent to 1.2 g of tablet so you have 42.3 mg/1.2 g tablet = 35.25 mg/g tablet
500 mg is 0.5 g, so 35.25 mg/g x 0.5 g = 17.625 mg phycocyanin/500 mg tablet
To two significant figures this is 18 mg phycocyanin/500 mg tablet
%(w/w) = 18 mg/500 (x100%) = 3.6% (w/w/)
Jazmin B.
We were also given a number of concentrations and absorbance values to make a graph. The equation of this graph was y=0.4174x - 0.04, with an R2 value of 0.9802
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12/03/17

J.R. S.
tutor
I didn't calculate the extinction coefficient. I looked it up. Also, since you have a standard curve, you won't need the extinction coefficient. The equation is in the form of a straight line, y = mx + b or Absorbance (O.D.) = (0.4174)(concentration) - 0.04. So, for your unknown sample, take the absorbance (O.D.) and add 0.04 and then divide that by 0.4174 to get the concentration in that sample. Then apply appropriate correction factors for the various dilutions that you make and aliquots that you took.
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12/03/17
Jazmin B.
12/03/17