Mark M. answered 11/15/17
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Retired math prof. Very extensive Precalculus tutoring experience.
cos(3θ) = -1
3θ = 180° + (360°k, where k = 0, ±1, ±2, ±3, ...
θ = 60° + (120°)k
If k = 0, then θ = 60°
If k = 1, then θ = 180°
If k = 2, then θ = 300°
Other choices of k give values of θ that are outside of the interval [0°, 360°].
Solutions: 60°, 180°, 300°