
David W. answered 11/08/17
Tutor
4.7
(90)
retired
This is a D-I-R-T (Distance Is Rate times Time) problem. D = R*T
So, T = D/R
" a track lap time of 1 minute while at a run" means running rate is (1 lap)/(1 minute)
"4 minutes while at a jog" means jogging rate is (1 lap)/(4 minutes)
"7 minutes while at a walk" means walking rate is (1 lap)/(7 minutes)
The distances are also given --
(2/5 lap) while running
(1/3 lap) while jogging
(4/15 lap( while walking
[note: good to check that (2/5 lap)+(1/3 lap)+4/15 lap) = (1 lap)]
6/15 + 5/15 + 4/15 = 15/15 = 1
"what is the total track lap time of the runner?"
Total time = time running + time jogging + time walking
= (2/5 lap) / ( (1 lap)/(1 min) ) + (1/3 lap) / ( (1 lap)/(4 min) ) + (4/15 lap) / ( (1 lap)/(7 min) )
NOTE: To divide by fraction, invert denominator and multiply. Lap cancels out.
= (2/5) min + (4/3) min + (48/15) min
= 6/15 min + 20/15 min + 48/15 min
NOTE: Least Common Denominator (LCD) is 15
= 74/15 min
= 4 14/15 min (also 4 minutes and 56 seconds)
So, T = D/R
" a track lap time of 1 minute while at a run" means running rate is (1 lap)/(1 minute)
"4 minutes while at a jog" means jogging rate is (1 lap)/(4 minutes)
"7 minutes while at a walk" means walking rate is (1 lap)/(7 minutes)
The distances are also given --
(2/5 lap) while running
(1/3 lap) while jogging
(4/15 lap( while walking
[note: good to check that (2/5 lap)+(1/3 lap)+4/15 lap) = (1 lap)]
6/15 + 5/15 + 4/15 = 15/15 = 1
"what is the total track lap time of the runner?"
Total time = time running + time jogging + time walking
= (2/5 lap) / ( (1 lap)/(1 min) ) + (1/3 lap) / ( (1 lap)/(4 min) ) + (4/15 lap) / ( (1 lap)/(7 min) )
NOTE: To divide by fraction, invert denominator and multiply. Lap cancels out.
= (2/5) min + (4/3) min + (48/15) min
= 6/15 min + 20/15 min + 48/15 min
NOTE: Least Common Denominator (LCD) is 15
= 74/15 min
= 4 14/15 min (also 4 minutes and 56 seconds)