J.R. S. answered • 11/06/17
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Write the balanced equation:
- Zn(s) + 2HCl(aq) ==> ZnCl2(aq) + H2(g)
Determine moles of Zn and moles of HCl being used:
- 22.0 g Zn x 1 mole Zn/65.38 g = 0.3365 moles Zn
- 14.0 g HCl x 1 mole HCl/36.5 g = 0.3836 moles HCl
Determine which reactant is limiting:
- Since it requires 2 moles HCl for every 1 mole Zn, the HCl is limiting and will determine mass of ZnCl2
Determine mass of ZnCl2 produced under these conditions:
- 0.3836 moles HCl x 1 mole ZnCl2/2 moles HCl x 136.3 g ZnCl2/mole ZnCl2 = 26.1 g ZnCl2 (to 3 sig. figs.)
Andrew H.
Use the following reaction: Zn + 2HCI -> ZnCl2 + H2. If 5.0 moles of HCl react with an excess amount of Zn, how many moles of ZnCl2 are produced? Make sure you show your work to get credit.03/21/21