Statistics questions z-score and raw score

Question

I'm stuck on this question, I know the formula for z score is  

Individual score - mean, divided by the standard deviation and the raw score is Z score times standard deviation + mean, but I just can't seem to get the correct answer.

Do i find the z score, plug it into the raw score formula and then find that number on the z-score table?

 

Here's the complete question:

 

A patient recently diagnosed with Alzheimer’s disease takes a cognitive abilities test and
scores a 45. The mean on this test is 52 and the standard deviation is 5.
What percentage of patients score below a raw score 45?
What percentage scores above a raw score 45?

 

Answer 1

Obtain a z-score chart

http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf

 

z = (X - μ) / σ

z = (45 - 52) / 5

z = -7 / 5

z = -1.4

 

Locate -1.4 under the "z" column. The firs number to the right (for a z of 1.40) is .0808

8.08% have lower scores.