Arthur D. answered 10/30/17
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2log(5)(x-3y)=log(5)(2x)+log(5)(2y)
log(5)(x-3y)2=log(5)(2x2y)
(x-3y)2=(2x2y)
(x-3y)2=4xy
x must be greater than 3y
x^2-6xy+9y^2=4xy
x^2-6xy-4xy+9y^2=0
x^2-10xy+9y^2=0
factor
(x-9y)(x-y)=0
x-y=0
x=y
x/y=1 but x>3y implies x/y>3 so disregard this answer
x-9y=0
x=9y
x/y=9 is the ratio