Complete solution. Chemistry world problem.

Question

Answer with solution:

500ml of a strong acid at 25 degrees celsius was neutralized with 500 ml with a strong base of 25 degrees celsius. After mixing acid and base, the final temperature attained by the nuetralized solution was 30 degrees celsius (assume 1g/ml for neutralized solution) find the heat of nuetralizated (in joules) for the reaction

Answer 1

Once again, you can use q = mC∆T

What is m (mass)?  The problem allows you to assume that the density of the acid and base is the same as water, and is taken as 1 g/ml. Then the mass is 500 g + 500 g = 1000 g.

 

Next, you also have to assume that the mixture has the same specific heat as water, which is 4.184 J/g/deg.  So, that is C.

Then the ∆T is the change in temperature which is 5 degrees.

 

Plug these into the equation and solve for q, the heat of reaction.