Philip P. answered • 10/30/17

Effective and Patient Math Tutor

m(t) = 15e

^{−0.087t}We want m(t) = 5 grams:

5 = 15e

^{−0.087t}(1/3) = e

^{−0.087t}ln(1/3) = −0.087t

ln(1/3)/(-0.087) = t days

Use you calculator to get the answer

K w.

asked • 10/30/17A 15 g sample of radioactive iodine decays in such a way that the mass remaining after t days is given by

m(t) = 15e^{−0.087t}, where m(t) is measured in grams.

m(t) = 15e

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Philip P. answered • 10/30/17

Effective and Patient Math Tutor

m(t) = 15e^{−0.087t}

We want m(t) = 5 grams:

5 = 15e^{−0.087t}

(1/3) = e^{−0.087t}

ln(1/3) = −0.087t

ln(1/3)/(-0.087) = t days

Use you calculator to get the answer

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