J.R. S. answered 10/26/17
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If you look at the electron configuration of aluminum (at. no. 13) you'll see it is 1s2 2s2 2p6 3s2 3p1. Note that the valence electrons (those in the 3rd energy level) number 3, i.e 2 in the 3s orbital, and 1 in the 3 p orbital. So, it wants to LOSE those 3 electrons to become stable. When it does that, it becomes an ion with a 3+ charge.