How many ml of 0.1 M HCl would be required to titrate 35 ml of 1 M NaOH to the end point?

Question

I need help answering this question for chemistry. Please show your work. Thank you.

Answer 1

At the equivalence point (end point in this question), the number of moles of HCl will equal the number of moles of NaOH.

 

Moles NaOH = 0.035 L x 1 mole NaOH/L = 0.035 moles NaOH

Now the question becomes "how many ml of 0.1 M HCl are required to produced 0.035 moles HCl (same moles as NaOH)

0.1 moles HCl/L (x L) = 0.035 moles HCl

Solve for x:  x = 0.035 moles/0.1 moles/L = answer in liters then x 1000 to get mls.