In the General reaction A + 2B --> C + 4D ∆H = -2367 kj/mol. What is the ∆H per mol of D?

Question

In the General reaction A + 2B --> C + 4D ∆H = -2367 kj/mol. What is the ∆H per mol of D?

Answer 1

This is a bizarre question, mainly because the ∆H of reaction doesn't refer to moles of any one substance in that reaction, but rather it refers to all of the substances with their associated stoichiometric coefficients.  Thus, in this reaction, it refers to the formation of 4 moles of D from 1 mole of A and 2 moles of B.  So, if you have to give an answer, it would be -2367/4.