A ball rolling down a hill was displaced 19.6m while uniformly accelerating from rest. If the final velocity was 5.00m/s. What was the rate of acceleration

Question

 A ball rolling down a hill was displaced 19.6m while uniformly accelerating from rest. If the final velocity was 5.00m/s. What was the rate of acceleration 

Answer 1

Use the kinematic relation

 

v_f² - v_i² = 2ad

 

v_f = final speed = 5.00 m/s

v_i = initial speed = 0

d = travel distance = 19.6 m

a = constant acceleration = ?

 

a = v_f²/(2d) = (5.00)²/[2(19.6)] m/s² ≅ 0.638 m/s²