Jhen N.

asked • 10/19/17

(tanθ+cotθ)^2=sec^2θ csc^2θ

Proving identities

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Arthur D. answered • 10/19/17

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(tanθ+cotθ)^2=sec^2θ+csc^2θ
tan^2θ+2tanθcotθ+cot^2θ=
tan^2θ+2tanθ(1/tanθ)+cot^2θ=
tan^2θ+2+cot^2&theta=;
substitute
sec^2θ-1+2+csc^2θ-1=
sec^2θ+csc^2θ
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Arthur D.

tutor
Editing changes things so &theta should be θ.
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10/19/17

Jhen N.

thank u ver much!
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10/19/17

Arthur D.

tutor
You're very welcome, Jhen.
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10/19/17

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