What is the value of K for this aqueous reaction at 298 K?

Question

A + B <-----> C + D   Delta G = 26.81 kJ/mol

Answer 1

∆G = -RT lnK

K = e^-∆G/RT

∆G/RT = 26.81kJ/mol/(0.008314 kJ/mol-K)(298K) = 10.82

K = e^-10.82

K = 2x10^-5