Calculating heat produced

Question

When 50.0 g of 0.200 M NaCl(aq) at 24.1 °C is added to 100.0 g of 0.100 M AgNO3(aq) at 24.1 °C in a calorimeter, the temperature increases to 25.2 °C as AgCl(s) forms. Assuming the specific heat of the solution and products is 4.20 J/g °C, calculate the approximate amount of heat in joules produced.

Answer 1

q = mC∆T

q = heat

m = mass = 50 g NaCl + 100 g AgNO3 = 150 g

C = specific heat = 4.20 J/g/deg

∆T = change in temperature = 25.2 - 24.1 = 1.1 degrees 

q = (150.0 g)(4.20 J/g/deg)(1.1 deg) = 693 joules