J.R. S. answered 10/17/17
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I already answered this and told you that in order to do this PROPERLY, you will need the density of the vinegar solution. If you don't want to do it properly, and you just want to assume a density of 1 g/ml (when it is actually 1.06 g/ml) then here is how to calculate the molarity.
5% by mass = 5 g/100 g and assuming a density of 1 g/ml that is the same as 5 g/100 ml
5 g/100 ml = 50 g/liter
50 g/liter x 1 mole/60 g = 0.83 moles/liter = 0.8 M
5% by mass = 5 g/100 g and assuming a density of 1 g/ml that is the same as 5 g/100 ml
5 g/100 ml = 50 g/liter
50 g/liter x 1 mole/60 g = 0.83 moles/liter = 0.8 M