write an equation of a line that is perpendicular to line a that passes through (2,2) with equation y = 5x - 8

Question

write an equation of a line that is perpendicular to line a that passes through (2,2) with equation y = 5x - 8

Answer 1

y = 5x - 8 is in slope intercept format:

y = mx + b where m is slope, b is y-intercept.

Slope is 5

 

Perpendicular lnes have slopes that are 

negative reciprocals... m_p = -1/m

 

You need equation of line through (2, 2)

with slope -1/5

 

y = (-1/5)x + b   where (2,2) is on the line.

2 = (-1/5)(2) + b

2 = -2/5 + b

b = 2 2/5  or 2.4  or  12/5

 

Your equation is:  y = (-1/5)x + 12/5

 

This can be reworked to standard form or left 

as is depending on your needs.

 

5y = -x + 12

x + 5y = 12