J.R. S. answered 10/09/17
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Iron(III) oxide is Fe2O3 and there are a couple of ways it can be reduced.
Fe2O3 + 3CO ==> 2Fe + 3CO2
2Fe2O3 + 3 C ==> 4Fe + 3CO2
The question didn't state what the reducing agent is, so I'll use the first one (carbon monoxide)
Fe2O3 + 3CO ==> 2Fe + 3CO2
moles Fe2O3 used = 320 g x 1 mole/160 g = 2 moles
moles CO2 produced = 2 moles Fe2O3 x 3 moles CO2/mole Fe2O3 = 6 moles CO2
Taking room temperature and pressure to be ~25ºC and 1 atm, then 1 mole = 24 liters
6 moles CO2 x 24 L/mole = 144 liters of CO2