J.R. S. answered 10/06/17
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How many electrons are in 147.80 g of sulfide ions?
Sulfide ion is S2-
S normally has 16 electrons as a neutral element. As a 2- ion, it will have 18 electrons.
147.8 g S2- x 1 mole/32.065 g x 6.02x1023 atoms/mole x 18 electrons/atom = 4.995x1025 electrons
Since your question asks about oxygen molecules (not oxygen atoms), it can be assumed to be asking about O2, not O.
Each O in O2 has 8 electrons, so in 1 molecule of O2 there are 16 electrons.
4.995x1025 electrons x 1 molecule O2/16 electrons = 3.122x1024 molecules O2
3.122x1024 molecules O2 x 1 mole O2/6.02x1024 molecules x 31.998 g/mole = 16.59 grams O2