J.R. S. answered 09/21/17
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2N2O(g) ==> 2N2(g) + O2(g)
The rate of change for the [N2O] = ∆[N2O]/2t = -0.015 M/s (note minus sign)
-∆[N2O]/2t = ∆[N2]/2t = ∆[O2]/t
Question is a little ambiguous because it doesn't state how the rate is measured. Is it 0.030 M/s N2 being formed? Is it 0.03 M/s O2 being formed?