
Jim J. answered 09/17/17
Tutor
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(181)
Experienced Math/Science Teacher available to help
Hi Joseph,
This is a cool problem.
First, we should define some variables:
Let X = total amount of money before any purchases.
Let b = the number of blouses purchased and B = the price of a blouse.
Let p = the number of pants purchased (2) and P = the price of pants.
OK, first sentence, "Raychel used 3/8 of her money to but blouses . . . this means that
(3/8)X = bB CALL THIS EQUATION 1
(bB is the amount spent on blouses - how many blouses times the price of each blouse)
Next part . . . "and 2/5 of the remainder to buy 2 pairs of pants."
If she spent (3/8)X on blouses, then (5/8)X remains . . . and 2/5 of that amount is 2/5 (5/8)X = (10/40)X = (1/4)X
So, (1/4)X was spent on pants. This means that
(1/4)X = 2P CALL THIS EQUATION 2
(2P is the amount spent on pants - 2 pants times the price of each pair of pants)
Last part . . . a pair of pants costs 3 times as much as a blouse.
So, P = 3B CALL THIS EQUATION 3
Now we just have to do some substitutions . . .
Equation 2 has a P, replace it with 3B (from equation 3)
(1/4)X = 2P
(1/4)X = 2(3B)
(1/4)X = 6B
Multiply both sides by 4 and
X = 24B
Replace the X in Equation 1 with 24 B
(3/8)X = bB
(3/8)(24B) = bB
72B/8 = bB
9B = bB
9 = b
Raychel bought 9 blouses.
Hope this helps! I had fun! :)

Jim J.
6th Grade????
Seems a little tough for 6th graders!
Glad I could help! :)
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09/17/17
Joseph D.
09/17/17