line that is perpendicular to y= 3/10 x -3

Question

plz help

 

Answer 1

Any line of slope 

 

m₂ = -1/(3/10) = -10/3 is perpendicular to the given line of slope

 

m₁ = 3/10.

 

The most general equation of the perpendicular line is

 

y = (-10/3)x + b,

 

where b is any real number.  For a complete solution, you will also need to state a point through which the line passes, and then we can solve for b.  

Answer 2

The given equation is in slope-intercept form: y = mx + b, therefor the slope (m) = 3/10. For a line to be perpendicular, the new slope must be -10/3 (opposite reciprocal of the old slope). Therefore a line that is perpendicular would be y = (-10/3)x - 3