J.R. S. answered  09/07/17
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You need to know the vapor pressure of pure water at the temperature of the experiment.  Neither vapor pressure nor temperature are given.  Assuming the temperature is 25ºC, you can look up the v.p. of pure water and it turns out to be 23.8 torr.
moles lactose = 35.00 g x 1 mole lactose/342 g = 0.102 moles
moles water = 110.0 g x 1 mole H2O/18 g = 6.11 moles
Total moles = 0.102 + 6.11 = 6.21 moles
mole fraction of H2O = 6.11/6.21 = 0.984
Vapor pressure of water (partial pressure of water) = 0.984 x 23.8 torr = 23.4 torr
     
        J.R. S.
tutor
                    In my original answer, it states that neither vapor pressure nor temperature is given.  The 55 degrees and 118.0 torr were added at a later date.  Look at how I answered the question, and it will be obvious that if 55º is used, that one would of course multiply the mole fraction (0.984) by the vapor pressure at that temperature (118.0 torr).
                
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            09/07/19
 
     
             
                     
                     
                    
Tori C.
i think you're supposed to multiply .984 by 118 torr, i got 115.8 torr and my professor said it's right09/07/19